(i) Q < R > P ... (ii)Combining both statements, we haveA > B < P < R > QNow, B < R is true.Hence, I follows.Again, We can?t compare A and Q. Thus, conclusion II does not follow.
Given:M < S<=T = R>=D > E>=F ...(i)
G<=S < H ...(ii)
Combining (i) and (ii), we get
G<=S<=T = R>=D > E>F andH > S<=T = R>=D > E>=F and
G<=S > M and M < S < H
(I) G = R is not true.
(II) G < R is not true.
But both are complamentary are pair.
I.A<=B<=D, So D>=A is true.
II. E>B > C, So E > C is true.
I. K>=L>O, So K>=O is not true
II. O< L = M<=N, So N>=O is not true.
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