Let the number of males be 'M'
Let the number of females be 'F'
From the given conditions,
(F-15)=2M.....(i)
F=5(M-45).....(ii)
By solving the equations (1) & (2) we get M = 80
Then substitute M = 80 in (1)
F = 2M + 15
F = 2 x 80 + 15
=> F = 175
Therefore, number of males = 80 and females = 175 in the party.
We know that when m is a odd number ( xm + am ) is divisible by ( x + a ).
? Each one is divisible by (41 + 43).
So Common factor = (41 + 43).
Certain sum for the person = (900 x 100)/(6 x 3) =Rs. 5000
? Interest on Rs. 5000 by C.I. = 5000(1 +6/100)3 - 5000 = Rs. 955.08
? More interest =Rs. (955.08 - 900) = Rs. 55.08
We know that , ?6 = 2.44, ?5 = 2.23, ?3 = 1.73
a = ?6 - ?5 = 2.44 - 2.23 = 0.21
b = ?5 - 2 = 2.23 - 2 = 0.23
c = 2 - ?3 = 2 - 1.73 = 0.27
Let the CP be Rs. x , then SP be 0.96x
? 0.96x = 240
? x = 250
Now the new SP = 250 X 1.1 = 275
Given expression 280.5 / 25.5 = 2805 / 255
= 2805 / (2.55 x 100)
= 1100 / 100
=11
Let age of Purvi = N yr
Then, age of Anil = 1.5N yr
According to the question,
(1.5N + 8)/(N + 8) = 25/18
? 27N + 144 = 25N + 200
? N = 56/2 = 28
Hence, present age of Purvi = 28 yr
Rs. 794.50 = 112.5 + (1/100) x Amount of stock
? Amount of stock = (794.50 x 100) / 113.5 = Rs. 700
Let us assume the salary of driver be ? R
Then Tips of week = R x 5/4
According to question,
his income during one week = Salary + Tips
? Total Income during one week = R + (5R/4)
? Total Income during one week = (4R + 5R)/4 = 9R/4
Required Fraction = Tips in a week/Total Income in a week
? Required Fraction = 5R/4 / 9R/4
? Required Fraction = 5R/4 x 4/9R
? Required Fraction = 5/9
Let required amount of coal be y metric tonnes
9 engines consumes 24 metric tonnes of coal in 8 hours a day.
More engines, more amount of coal (direct proportion)
If 3 engines of first type consume 1 unit, then 1 engine will consume 1/3 unit which is its the rate of consumption.
If 4 engines of second type consume 1 unit, then 1 engine will consume 1/4 unit which is its the rate of consumption
More rate of consumption, more amount of coal (direct proportion)
More hours, more amount of coal(direct proportion)
Now we have , 9 × ( 1 / 3 ) × 8 × y = 8 × ( 1 / 4 ) × 13 × 24
? 3 × 8 × y = 8 × 6 × 13
? 3 × y = 6 × 13 ? y = 2 x 13 = 26 metric tonnes
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