S.I. for 3 years = Rs. (12005 - 9800) = Rs. 2205.
S.I. for 5 years = Rs. = Rs.3675
Principle = Rs.(9800-3675) = Rs.6125
Hence, Rate = =12%
2500 in 5th year and 3000 in 7th year
So in between 2 years Rs. 500 is increased => for a year 500/2 = 250
So, per year it is increasing Rs.250 then in 5 years => 250 x 5 = 1250
Hence, the initial amount must be 2500 - 1250 = Rs. 1250
Principle amount = Rs. 29000
Interest = Rs. 10440
Let rate of interest = r%
=> So, time = r years
According to the question,
10440 = 29000 x r x r/100
290 x r x r = 10440
r x r = 1044/29 = 36
r = 6
Hence, the rate of interest = 6% and time = 6 yrs.
(24 + 31 + 18) days = 73 days = 1/5 year .
P = Rs 3000 and R = 18 % p.a.
P --- 10 ----- 600
P --- 5 ----- 300
3P --- 5 ----- 900
__________
1200
Here given Interest earned = Rs. 2260
Time = 3 years
Rate of interest = ?
Principal Amount = ?
So, it can't be determined.
Let the sum invested be Rs. P
Let the rate of interest be R% per annum
=> Interest earned for 5 years = (P x 5 x R/100) = PR/20
Now, given that the interest earned increased by Rs. 600 if the Rate increased to (R+2)%
=> SI = (P x 5 x (R+2))/100 = PR/20 + 10P/100
Hence,
PR/20 + 10P/100 = PR/20 + 600
=> P = 6000
Therefore, the sum invested is Rs. 6000
Let the principle amount be Rs. P
Interest rate = 12%
Total amount he paid after 5 years = Rs. 1280
ATQ,
Hence, the amount he borrowed = P = Rs. 800.
S.I. = Rs. (15500 - 12500) = Rs. 3000.
Rate = % = 6%
We know that I = PTR/100
=> P = 20250/4.5 = 4500
Now, new Interest at 5% = 4500x1x5/100 = 225
Now the additional amount = 225 - 202.5 = Rs. 22.5
As the interest rate increases by 2%
=> (7000x3x2)/100 = 420
9200
--------
9620
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.