Let the speed of the faster train be 'S' kmph
Then speed of the slower train will be '(S-5)' kmph
Time taken by faster train = 350/S hrs
Time taken by slower train = 350/(S-5) hrs
=> S = 30 km/hr.
Speed =[ 72 x (5/18) ]m/sec= 20 m/sec.
Time = 26 sec.
Let the length of the train be x metres.
Then,[ (x+250)/26 ]= 20
=> x + 250 = 520
=> x = 270.
Let 'd' be the distance and 's' be the speed and 't' be the time
d=sxt
45 mins = 3/4 hr and 48 mins = 4/5 hr
As distance is same in both cases;
s(3/4) = (s-5)(4/5)
3s/4 = (4s-20)/5
15s = 16s-80
s = 80 km.
=> d = 80 x 3/4 = 60 kms.
Given speed = 63 km/hr = m/s
Let the length of the bridge = x mts
Given time taken to cover the distance of (170 + x)mts is 30 sec.
We know speed = m/s
--> x = 355 mts.
Distance = 70 x 1 ½ = 105 km
Relative Speed = 85 ? 70 = 15
Time = 105/15 = 7 hrs
4:30 + 7 hrs = 11.30 p.m.
We know that
distance= speed * time
d= 100 mts.
As Trains are moving in same direction,
Relative Speed = 60-20 = 40 kmph
--> m/sec
Length of Train= Speed * Time
Length =
Speed of the Train K is given by s = d/t = 240/20 = 12 m/s
Distance covered by Train K in 50 seconds = 12 x 50 = 600 mts.
But it crosses Train L in 50 seconds
Therefore, the length of the Train L is = 600 - 240 = 360 mts.
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