99 = 1 x 3 x 3 x 11
101= 1 x 101
176= 1 x 2x 2 x 2 x 2 x 11
182= 1 x 2 x 7 x 13
So, divisors of 99 are 1, 3, 9, 11, 33, 99
divisors of 101 are 1,101
divisors of 176 are 1, 2, 4, 8, 16, 22, 44, 88, 176
divisors of 182 are 1, 2, 7, 13, 14, 26, 91, 182
Hence , 176 hasthe most number of divisors.
LCM of 9,10,12,15 is 180
Smallest natural number to get remainder of 3 is (180 + 3) = 183
Let the numbers be a and b . Then, a+b =55 and ab = 5 x 120 = 600.
Therefore, Required sum =
The smallest possible number of books = L.C.M of 5, 9 and 13.
Therefore, L.C.M of 5,9 and 13 is = 5 x 9 x 13 = 585.
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