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- Question
In a palace, three different types of coins are there namely gold, silver and bronze. The number of gold, silver and bronze coins is 18000, 9600 and 3600 respectively. Find the minimum number of rooms required if in each room should give the same number of coins of the same type ?
Options- A. 26
- B. 24
- C. 18
- D. 12
- Correct Answer
- 26
ExplanationGold coins = 18000 , Silver coins = 9600 , Bronze coins = 3600
Find a number which exactly divide all these numbers
That is HCF of 18000, 9600& 3600
All the value has 00 at end so the factor will also have 00.
HCF for 180, 96 & 36.
Factors of
180 = 3 x 3 x 5 x 2 x 2
96 = 2 x 2 x 2 x 2 x 2 x 3
36 = 2 x 2 x 3 x 3
Common factors are 2x2×3=12
Therefore, Actual HCF is 1200
Gold Coins 18000/1200 will be in 15 rooms
Silver Coins 9600/1200 will be in 8 rooms
Bronze Coins 3600/1200 will be in 3 rooms
Total rooms will be (15+8+3) = 26 rooms.
- 1. Three numbers are in the ratio of 3:4:5 and their L.C.M is 3600.Their HCF is:
Options- A. 40
- B. 60
- C. 100
- D. 120 Discuss
- 2. Find the least common multiple of 15 and 12?
Options- A. 3
- B. 12
- C. 30
- D. 60 Discuss
- 3. Find the greatest number that will divide 964, 1238 and 1400 leaving remainder of 41,31 and 51 respectively ?
Options- A. 64
- B. 69
- C. 71
- D. 58 Discuss
- 4. The G.C.D of 1.08, 0.36 and 0.9 is
Options- A. 0.9
- B. 0.36
- C. 0.18
- D. 1.08 Discuss
- 5. If N is the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. What is the sum of the digits of N ?
Options- A. 6
- B. 8
- C. 4
- D. 9 Discuss
- 6. Three different containers contain 1365 litres, 1560 litres and 1755 litres of mixtures of milk and water respectively. What biggest measure that can measure all the different quantities exactly ?
Options- A. 37 lit
- B. 97 lit
- C. 129 lit
- D. 195 lit Discuss
- 7. Find the HCF of 865 and 2595.
Options- A. 25
- B. 2595
- C. 865
- D. 5 Discuss
- 8. The LCM of 72 and 84 is:
Options- A. 12 × 6 × 7
- B. 6 × 2 × 7
- C. 12 × 7 × 3
- D. 72 × 84 Discuss
- 9. A natural number, when divided by 9, 10, 12 or 15, leaves a remainder of 3 in each case. What is the smallest of all such numbers?
Options- A. 183
- B. 153
- C. 63
- D. 123 Discuss
- 10. The product of two 2-digit numbers is 2160 and their H.C.F. is 12. The numbers are
Options- A. (12, 60)
- B. (72, 30)
- C. (36, 60)
- D. (60, 72) Discuss
Search Results
Correct Answer: 60
Explanation:
Let the numbers be 3x, 4x, 5x.
Then, their L.C.M = 60x.
So, 60x=3600 or x=60.
Therefore, The numbers are (3 x 60), (4 x 60), (5 x 60).
Hence,required H.C.F=60
Correct Answer: 60
Explanation:
The least common multiple of 12 and 15 is
12 = 2 x 2 x 3
15 = 3 x 5
LCM of 12 and 15 is 2 x 2 x 3 x 5 = 60.
Correct Answer: 71
Explanation:
To find the greatest number which divides the numbers 964, 1238 and 1400 leaving the remainders 41, 31 and 51 is nothing but the HCF of (964 - 41), (1238 - 31), (1400 - 51).
Therefore, HCF of 923, 1207 and 1349 is 71.
Correct Answer: 0.18
Explanation:
G.C.D is nothing but H.C.F
Given numbers are 1.08 , 0.36 and 0.90
we can take as 108, 36 and 90
Then required H.C.F is 18.
Therefore, H.C.F of given numbers is 0.18.
Correct Answer: 4
Explanation:
N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)
= H.C.F. of 3360, 2240 and 5600 = 1120.
Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4
Correct Answer: 195 lit
Explanation:
From the given data,
containers contain mixtures of milk and water as 1365 lit, 1560 lit and 1755 lit.
Biggest measure that can measure all these different quantities exactly can be given by
HCF of (1365, 1560, 1755)
That can be found as
HCF of 1365, 1755 = 195
Now, HCF of 195 and 1560 = 195
Hence, biggest measure that can measure all the given different quantities exactly is 195 lit.
Correct Answer: 865
Correct Answer: 12 × 6 × 7
Correct Answer: 183
Explanation:
LCM of 9,10,12,15 is 180
Smallest natural number to get remainder of 3 is (180 + 3) = 183
Correct Answer: (36, 60)
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