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Home ‣ Aptitude ‣ HCF and LCM Comments
- Question
HCF of 1, 2, 3?
Options- A. 3
- B. 2
- C. 1
- D. 0
- Correct Answer
- 1
ExplanationGiven numbers are 1, 2 and 3
Factors of 1 = 1
Factors of 2 = 1, 2
Factors of 3 = 1, 2 and 3
Common factors = 1
Hence, the HCF of 1, 2 and 3 = 1.
- 1. The largest measuring cylinder that can accurately fill 3 tanks of capacity 98, 182 and 266 litres each, is of capacity ?
Options- A. 7 lts
- B. 14 lts
- C. 98 lts
- D. 42 lts Discuss
- 2. Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ?
Options- A. 4
- B. 10
- C. 15
- D. 16 Discuss
- 3. H.C.F of 3240, 3600 and a third number is 36 and their L.C.M is 2 4 x 3 5 x 5 2 x 7 2 . What is the third number?
Options- A. 47628
- B. 49874
- C. 24157
- D. 42146 Discuss
- 4. Find the lowest common multiple of 24, 36 and 40?
Options- A. 360
- B. 420
- C. 240
- D. 120 Discuss
- 5. A room is 6 meters 24 centimeters in length and 4 meters 32 centimeters in Width. Find the least number of square tiles of equal size required to cover the entire floor of the room.
Options- A. 107
- B. 117
- C. 127
- D. 137 Discuss
- 6. If N is the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. What is the sum of the digits of N ?
Options- A. 6
- B. 8
- C. 4
- D. 9 Discuss
- 7. The G.C.D of 1.08, 0.36 and 0.9 is
Options- A. 0.9
- B. 0.36
- C. 0.18
- D. 1.08 Discuss
- 8. Find the greatest number that will divide 964, 1238 and 1400 leaving remainder of 41,31 and 51 respectively ?
Options- A. 64
- B. 69
- C. 71
- D. 58 Discuss
- 9. Find the least common multiple of 15 and 12?
Options- A. 3
- B. 12
- C. 30
- D. 60 Discuss
- 10. Three numbers are in the ratio of 3:4:5 and their L.C.M is 3600.Their HCF is:
Options- A. 40
- B. 60
- C. 100
- D. 120 Discuss
Search Results
Correct Answer: 14 lts
Explanation:
To know the the measuring cylinder that can fill all the given capacities , they must be divisible by the required number.
98,182,266 all are divisible by 14
So 14 litres is the largest cylinder that can fill all the given cylinders.
(or)
The other method is take HCF of all given capacities i.e 98, 182 and 266.
Correct Answer: 16
Explanation:
L.C.M. of 2, 4, 6, 8, 10, 12 is 120.
So, the bells will toll together after every 120 seconds(2 minutes).
In 30 minutes,they will together (30/2)+1=16 times
Correct Answer: 47628
Correct Answer: 360
Explanation:
To find the LCM of 24, 36 and 40
24 = 2 x 2 x 2 x 3
36 = 2 x 2 x 3 x 3
40 = 2 x 2 x 2 x 5
Now, LCM of 24, 36 and 40 = 2 x 2 x 2 x 3 x 3 x 5
= 8 x 9 x 5
= 72 x 5
= 360
Correct Answer: 117
Explanation:
Let us calculate both the length and width of the room in centimeters.
Length = 6 meters and 24 centimeters = 624 cm
width = 4 meters and 32 centimeters = 432 cm
As we want the least number of square tiles required, it means the length of each square tile should be as large as possible.Further,the length of each square tile should be a factor of both the length and width of the room.
Hence, the length of each square tile will be equal to the HCF of the length and width of the room = HCF of 624 and 432 = 48
Thus, the number of square tiles required = (624 x 432 ) / (48 x 48) = 13 x 9 = 117
Correct Answer: 4
Explanation:
N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)
= H.C.F. of 3360, 2240 and 5600 = 1120.
Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4
Correct Answer: 0.18
Explanation:
G.C.D is nothing but H.C.F
Given numbers are 1.08 , 0.36 and 0.90
we can take as 108, 36 and 90
Then required H.C.F is 18.
Therefore, H.C.F of given numbers is 0.18.
Correct Answer: 71
Explanation:
To find the greatest number which divides the numbers 964, 1238 and 1400 leaving the remainders 41, 31 and 51 is nothing but the HCF of (964 - 41), (1238 - 31), (1400 - 51).
Therefore, HCF of 923, 1207 and 1349 is 71.
Correct Answer: 60
Explanation:
The least common multiple of 12 and 15 is
12 = 2 x 2 x 3
15 = 3 x 5
LCM of 12 and 15 is 2 x 2 x 3 x 5 = 60.
Correct Answer: 60
Explanation:
Let the numbers be 3x, 4x, 5x.
Then, their L.C.M = 60x.
So, 60x=3600 or x=60.
Therefore, The numbers are (3 x 60), (4 x 60), (5 x 60).
Hence,required H.C.F=60
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