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Home ‣ Aptitude ‣ HCF and LCM Comments
- Question
If HCF of two numbers is 8,which of the following can never be their LCM?
Options- A. 32
- B. 48
- C. 60
- D. 152
- Correct Answer
- 60
Explanation60 is not a multiple of 8
- 1. The H.C.F of two numbers is 11 and their L.C.M is 7700. If one of the numbers is 275 , then the other is
Options- A. 279
- B. 283
- C. 308
- D. 318 Discuss
- 2. The product of two numbers is 4107. If the H.C.F of these numbers is 37, then the greater number is
Options- A. 101
- B. 107
- C. 111
- D. 185 Discuss
- 3. H.C.F of 4 x 27 x 3125, 8 x 9 x 25 x 7 and 16 x 81 x 5 x 11 x 49 is
Options- A. 180
- B. 360
- C. 540
- D. 1260 Discuss
- 4. Three numbers are in the ratio 1 : 2 : 3 and their H.C.F is 12. The numbers are
Options- A. 4, 8, 12
- B. 5, 10, 15
- C. 10, 20, 30
- D. 12, 24, 36 Discuss
- 5. The H.C.F and L.C.M of two numbers are 11 and 385 respectively. If one number lies between 75 and 125 , then that number is
Options- A. 77
- B. 88
- C. 99
- D. 110 Discuss
- 6. The least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is
Options- A. 1677
- B. 1683
- C. 2523
- D. 3363 Discuss
- 7. A heap of coconuts is divided into groups of 2, 3 and 5 and each time one coconut is left over. The least number of Coconuts in the heap is ?
Options- A. 63
- B. 31
- C. 16
- D. 27 Discuss
- 8. LCM of 80, 85, 90
Options- A. 11440
- B. 11998
- C. 12240
- D. 12880 Discuss
- 9. A drink vendor has 368 liters of Maaza, 80 liters of Pepsi and 144 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required ?
Options- A. 47
- B. 46
- C. 37
- D. 35 Discuss
- 10. The maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is:
Options- A. 91
- B. 910
- C. 1001
- D. 1911 Discuss
Search Results
Correct Answer: 308
Explanation:
Other number = = 308
Correct Answer: 111
Explanation:
Let the numbers be 37a and 37b. Then , 37a x 37b =4107 => ab = 3.
Now co-primes with product 3 are (1,3)
So, the required numbers are (37 x 1, 37 x 3) i.e, (37,111).
Therefore, Greater number = 111.
Correct Answer: 180
Correct Answer: 12, 24, 36
Explanation:
Let the required numbers be x, 2x, 3x. Then, their H.C.F =x. so, x= 12
Therefore, The numbers are 12, 24, 36
Correct Answer: 77
Explanation:
Product of numbers = 11 x 385 = 4235
Let the numbers be 11a and 11b . Then , 11a x 11b = 4235 => ab = 35
Now, co-primes with product 35 are (1,35) and (5,7)
So, the numbers are ( 11 x 1, 11 x 35) and (11 x 5, 11 x 7)
Since one number lies 75 and 125, the suitable pair is (55,77)
Hence , required number = 77
Correct Answer: 1683
Explanation:
L.C.M of 5, 6, 7, 8 = 840
Therefore, Required Number is of the form 840k+3.
Least value of k for which (840k+3) is divisible by 9 is k = 2
Therefore, Required Number = (840 x 2+3)=1683
Correct Answer: 31
Explanation:
To get the least number of coconuts :
LCM = 30 => 30 + 1 = 31
Correct Answer: 12240
Explanation:
LCM of (80, 85, 90) can be found by prime factorizing them.
80 ? 2 × 2 × 2 × 2 × 5
85 ? 17 × 5
90 ? 2 × 3 × 3 × 5
L.C.M of (80,85,90) = 2 × 2 x 2 × 2 × 3 × 3 × 5 × 17
= 16 x 9 x 85
= 144 x 85
= 12240
L.C.M of (80,85,90) = 12240.
Correct Answer: 37
Explanation:
The number of liters in each can = HCF of 80, 144 and 368 = 16 liters.
Number of cans of Maaza = 368/16 = 23
Number of cans of Pepsi = 80/16 = 5
Number of cans of Sprite = 144/16 = 9
The total number of cans required = 23 + 5 + 9 = 37 cans.
Correct Answer: 91
Explanation:
Required number of students = H.C.F of 1001 and 910 = 91
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