In this type of problems the formulae is
x is replaced by the first interval of given time Here i.e 8
=
min
Therefore the hands will be in the same straight line but not
together at
min.past 8.
55min spaces are covered in 60min
60 min. spaces are covered in (60/55 x 60) min= 65+5/11 min.
loss in 64min=(65+5/11)- 64 =16/11
Loss in 24 hrs (16/11 x 1/64 x 24 x 60) min= 32 8/11.
Angle traced by hour hand in 17/2 hrs = = 255
Angle traced by min hand in 30 min = = 180
Therefore, Required angle = (255 - 180) =
At 5 o'clock, the hands are 25 min. spaces apart.
To be at right angles and that too between 5.30 and 6, the minute hand has to gain (25 + 15) = 40 min. spaces.
55 min. spaces are gained in 60 min
40 min. spaces are gained in min
this type of problems the formulae is
(5*x + or -15)*(12/11)
Here x is replaced by the first interval of given time
here i.e 4
Case 1 : (5*x + 15)*(12/11)
(5*4 +15)*(12/11)
(20+15)*(12/11)
35*12/11=420/11=38 2/11 min.
Therefore they are right angles at 38 2/11 min .past4
Case 2 : (5*x-15)*(12/11)
(5*4-15)*(12/11)
(20-15)*(12/11)
5*12/11=60/11 min=5 5/11min
Therefore they are right angles at 5 5/11 min.past4.
Time from 12 p.m on monday to 2 p.m on the following monday = 7 days 2 hours = 170 hours
Therefore, The watch gains min. or 34/5 min. in 170 hrs.
Now, 34/5 min. are gained in 170 hrs.
Therefore, 2 min are gained in hrs = 50 hrs
Therefore, Watch is correct 2 days 2 hrs. after 12 p.m on monday i.e it will be correct at 2 p.m on wednesday.
The watch gains 5 seconds in 3 minutes = 100 seconds in 1 hour.
From 8 AM to 10 PM on the same day, time passed is 14 hours.
In 14 hours, the watch would have gained 1400 seconds or 23 minutes 20 seconds.
So, when the correct time is 10 PM, the watch would show 10 : 23 : 20 PM
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