Discussion
Home ‣ Aptitude ‣ HCF and LCM Comments
- Question
A rectangular courtyard 3.78 meters long 5.25 meters wide is to be paved exactly with square tiles, all of the same size. what is the largest size of the tile which could be used for the purpose?
Options- A. 14 cms
- B. 21 cms
- C. 42 cms
- D. None of these
- Correct Answer
- 21 cms
Explanation3.78 meters =378 cm = 2 × 3 × 3 × 3 × 7
5.25 meters=525 cm = 5 × 5 × 3 × 7
Hence common factors are 3 and 7
Hence LCM = 3 × 7 = 21
Hence largest size of square tiles that can be paved exactly with square tiles is 21 cm.
- 1. Convert the 0.0068 in to vulgar fraction:
Options- A. 7/1250
- B. 17/2500
- C. 17/5000
- D. 7/1750 Discuss
- 2. Sum of four times a fraction and 6 times its reciprocal is 11. What is the fraction?
Options- A. 3/4
- B. 4/3
- C. 4/7
- D. 7/4 Discuss
- 3. Sum of twice a fraction and 3 times its reciprocal is 29/3. What is the fraction?
Options- A. 2/9
- B. 5/4
- C. 4/5
- D. 9/2 Discuss
- 4. The sum of a fraction and 3 times its reciprocal is 31/6. What is the fraction?
Options- A. 2/9
- B. 9/2
- C. 5/4
- D. 4/5 Discuss
- 5. Reduce 2714/5074 to lowest terms.
Options- A. 17/23
- B. 29/43
- C. 23/43
- D. 31/37 Discuss
- 6. The L.C.M of 22, 54, 108, 135 and 198 is
Options- A. 330
- B. 1980
- C. 5940
- D. 11880 Discuss
- 7. Product of two co-prime numbers is 117. Their L.C.M should be
Options- A. 1
- B. 117
- C. Equal to their H.C.F
- D. cannot be calculated Discuss
- 8. The L.C.M of two numbers is 495 and their H.C.F is 5. If the sum of the numbers is 100, then their difference is
Options- A. 10
- B. 46
- C. 70
- D. 90 Discuss
- 9. L.C.M of two prime numbers x and y (x>y) is 161. The value of 3y-x is :
Options- A. -2
- B. -1
- C. 1
- D. 2 Discuss
- 10. If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:
Options- A. 55/601
- B. 601/55
- C. 11/120
- D. 120/11 Discuss
Search Results
Correct Answer: 17/2500
Correct Answer: 3/4
Correct Answer: 9/2
Correct Answer: 9/2
Correct Answer: 23/43
Correct Answer: 5940
Explanation:
22 = 2 x 11
54 =
108 =
135 =
198 =
Correct Answer: 117
Explanation:
H.C.F of co-prime numbers is 1. So, L.C.M = 117/1 =117
Correct Answer: 10
Explanation:
Let the numbers be x and (100-x).
Then,
=>
=> (x-55) (x-45) = 0
=> x = 55 or x = 45
The numbers are 45 and 55
Required difference = (55-45) = 10
Correct Answer: -2
Explanation:
H. C. F of two prime numbers is 1. Product of numbers = 1 x 161 = 161.
Let the numbers be a and b . Then , ab= 161.
Now, co-primes with product 161 are (1, 161) and (7, 23).
Since x and y are prime numbers and x >y , we have x=23 and y=7.
Therefore, 3y-x = (3 x 7)-23 = -2
Correct Answer: 11/120
Explanation:
Let the numbers be a and b.
Then, a + b = 55 and ab = 5 x 120 = 600.
The required sum = = = =
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