The above figure contains 4 boxes were two are similar. This particular box contains 8 triangles and 1 square, as there are two boxes which are same, then there are total 16 triangles and 2 squares.
The above figure contains :: (16 triangles and 3 squares) x 2 = 32 triangles and 6 squares.
Total triangles = 48 and total squares = 8
As per given figure, Please check the below number and count the triangles .
There are total 24 triangles. The way to count the triangles of the figure is to draw the figure and count.
TOTAL NUMBER OF QUADRILATERALS = 17
The total number of triangles present in the above figure is 20
Number of Triangle are ABG, AJC, EFD, DIB, AIH, EIJ, BJF, CFG, DGH, JFG, IJG, HJG, IOH, IOJ, IOG, HOG.
Total: 19
Solve by using all option one by one.
Given equation is
24 * 16 * 8 * 32
Taking the sign of option (D),
? 24 + 16 - 8 = 32
Apply the BODMAS Rule in equation.
? 40 - 8 = 32 ? 32 = 32
Hence, correct group of sign is option (b).
The Multiples of 18 are 18, 36, 54, 72, 90, 108, 126, ....
Acording to the above stated passage only the argument " The nearsightedness in the children is caused by the ...........visual stress required by reading and other class work." will be true
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