From I: There are two possible arrangetments.
(a) P T R S
(B) P T R S
So, either T or R
From II: There are two possible arrangements.
(a) Q T S
(b) T S Q
Again either T or S
Combining I and II
From above given pie-chart , we can see that
Number of boys for difference courses are
A = 0; B = 100; C = 44; D = 180; E = 32; F = 44.
Hence ,C and F pair of courses are the number of boys the same .
Required percentage |
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= 88.54% | ||||||||
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From I: 5$#3 = flowers are really good ..........(i)
From II: 7#35 = good flowers are available .......(ii)
From I and II: 5#3 = Flowers are good ...........(iii)
Putting (iii) in (i), we get $ = Really
Given that their salaries are in the ratio of 3:4 and expenditure is in the ratio of 4:5 hence we can assume that salary of A and B are 3x and 4x and their expenditures are 4y and 5y.
Now we need to find the ratio of (3x - 4y)/(4x - 5y)
Consider statement I alone:
Giving of B is 25% of his salary hence his expenditure must be 75% so 3/4(4x) = 5y or 3x = 5y from this we can find the required ratio hence this statement is sufficient.
Consider statement II alone :
Given that 4x = 2000 or x = 500 but from this we can not find the value of y and hence we can not find the ratio of their savings.
Total number of girls enrolled in painting in the Institutes A and C = 250 + 150 = 400
Total number of girls enrolled in painting in the Institutes D and E = 250 + 325 = 575
Required ratio = 400 : 575 = 16 : 23
Data inadequate
So ,Required answer cannot be determined.
Consider Statement I alone
Given that Area (?ABC) = Area(?PQR) since nothing about the sides or angles is mentioned, we can not say if they are congruent.Hence, I alone is not sufficient.
Consider Statement II alone
?ABC and ?PQR are right triangles. Nothing about the sides is given, Hence, II alone is not sufficient. Now using both I and II
Now we have two right angled triangle k with same area we may have different combination as only product of base and height is same. Hence even by using both the statement we can not find the answer.
From 1: he is sure = ja ha ma
From II: is she sure = ka ja ma
Combining the two, we get
Is sure = ja ma
Hence, sure = ja or ma
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