From Statement I,
SI = PRT/100
? P = (P x R x 10)/100
? R = 10%
From Statement II,
Difference (D) = PR2/(100)2
? 150 = (15000 x R2)/10000
? R = 10%
Thus, either Statement I or II is sufficient.
(A + B)'s 1 day's work = 1/8 ..........(i)
(B + C)'s 1 day's work = 1/10 ..........(ii)
(C + A)'s 1 day's work = 1/12 ............(iii)
Add the equation (i), (ii), (iii)
2(A + B + c)'s 1 day's work = 1/8 + 1/10 + 1/12
(A + B + C)'s 1 day's work = 1/2[1/8 + 1/10 + 1/12] ..........(iv)
Subtracting Eq. (iii) from Eq. (iv), we get B's 1 day's work.
then, required number of days = 1/(B's 1 day's work) .
So we need all above 3 statements to solve the given question.
Form Statement I,
R A G E
Clearly , the left place or empty place is filled by N .
From Statement II ,
A N G
G N A
Clearly N is at third place ,
Hence, the data in Statement I alone or in Statement II alone are sufficient to answer the question .
From Statement I,
N > M > K
From Statement II ,
L > N
From both the Statement
L > N > M > K
but height of J is not clear .
Thus second tallest friend cannot be determined.
Hence, data neither in Statement I nor in Statement II are sufficient to answer the question .
From Statement I,
Number of student in the class
= 21 or 22 or 23 or 24 or 25 or 26
From Statement II,
Number of student in the class
= 25 or 26 or 27 or 28 or 29 or 30
Sine , number of student can be divided into group of 5 students, therefore number of student must be multiple of 5.
? NUmber of student in the class = 25 or 30
Combining Statement I and II .
Number of Student in the class = 25
Hence , the data in both the Statement I and II together are necessary to answer the question .
From Statement I L is the husband of D . as L has three children , D also has three children .
From Statement II, N, S and P are siblings and are the children of L and of D also . Thus , D is the mother of S .
Hence , data in both the Statement I and II together are necessary to answer the question .
From Statement I and III,
Let marks in English be x
Marks in Science = x + 12
and marks in Mathematics = x + 32
From Statement II,
E + S + M = 197
x + x + 12 + x + 32 = 197
? 3x + 44 = 197
? 3x = 197 - 44 = 153
? x = 51
? Marks in English = 51
(X + Y)'s 1 day's work = 1/8 ..(i)
(Y + Z)'s 1 day's work = 1/10 ...(ii)
(Z + X)'s 1 day's work = 1/12 ..(iii)
Adding equations i , ii , iii
2(X + Y + Z)'s 1 day's work = 1/8 + 1/10 + 1/12
(X + Y + Z)'s 1 day's work
= 1/2[1/8 + 1/10 + 1/12] ..(iv)
Subtracting Eq. (iii) from Eq. (iv), we get Y's 1 day's work,
Then, required number of days
= 1/Y's 1 day's work
Data are not sufficient even from Statement I and II both.
From Statement I,
R = (SI x 100) / (P x T)
? (1736 x 100)/(6200 x 2) = 14%
From Statement II,
1348.2 4500(1 + r/100)2 - 4500
? 1348.2 + 4500 = 4500(1 + r/100)2
? 5848.2 = 4500((1 + r/100)2
? 5848.2/4500 = (1 + r/100)2
? 3249/2500 = (1 + r/100)2
? (57/50)2 = (1 + r/100)2
? 1 + r/100 = 57/50
? r/100 = 57/50 - 1 = 7/50
? r = 7 x 100/50
? r = 14%
Both statement are alone sufficient.
Data given in Statement I alone are sufficient to answer the question
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