From Statement I,
N > M > K
From Statement II ,
L > N
From both the Statement
L > N > M > K
but height of J is not clear .
Thus second tallest friend cannot be determined.
Hence, data neither in Statement I nor in Statement II are sufficient to answer the question .
From Statement I,
Number of student in the class
= 21 or 22 or 23 or 24 or 25 or 26
From Statement II,
Number of student in the class
= 25 or 26 or 27 or 28 or 29 or 30
Sine , number of student can be divided into group of 5 students, therefore number of student must be multiple of 5.
? NUmber of student in the class = 25 or 30
Combining Statement I and II .
Number of Student in the class = 25
Hence , the data in both the Statement I and II together are necessary to answer the question .
From Statement I L is the husband of D . as L has three children , D also has three children .
From Statement II, N, S and P are siblings and are the children of L and of D also . Thus , D is the mother of S .
Hence , data in both the Statement I and II together are necessary to answer the question .
From Statement I,
tell me the cost ? @ 0 # 9
cost wase very high ? & 6 # 1
? cost ? #
From Statement II ,
Some cost was discount ? 1 6 7 #
Some people like discount ? 8 7 5 %
? some discount ? 8 7 and cost ? either 1 or #
Thus we can the code of 'cost' from Statement I only.
Hence, data in Statement I alone are sufficient to answer the question.
Statement I,
40/100 xx = 20/100 x 50 ? x = 25
Statement II,
30/100 x y = 25/100 x 72 ? y = 60
From both statements,
x : y = 25 : 60 = 5 : 12
From Statement I,
D + E = 14 x 2 = 28
From Statement II,
A + B + C + D + E + F = 4 x 50 = 200
(A + B + C + D + E + F)/6 = 28 + 200/6
= 228/6 = 38
? Statement I and II are sufficient to answer the question.
Form Statement I,
R A G E
Clearly , the left place or empty place is filled by N .
From Statement II ,
A N G
G N A
Clearly N is at third place ,
Hence, the data in Statement I alone or in Statement II alone are sufficient to answer the question .
(A + B)'s 1 day's work = 1/8 ..........(i)
(B + C)'s 1 day's work = 1/10 ..........(ii)
(C + A)'s 1 day's work = 1/12 ............(iii)
Add the equation (i), (ii), (iii)
2(A + B + c)'s 1 day's work = 1/8 + 1/10 + 1/12
(A + B + C)'s 1 day's work = 1/2[1/8 + 1/10 + 1/12] ..........(iv)
Subtracting Eq. (iii) from Eq. (iv), we get B's 1 day's work.
then, required number of days = 1/(B's 1 day's work) .
So we need all above 3 statements to solve the given question.
From Statement I,
SI = PRT/100
? P = (P x R x 10)/100
? R = 10%
From Statement II,
Difference (D) = PR2/(100)2
? 150 = (15000 x R2)/10000
? R = 10%
Thus, either Statement I or II is sufficient.
From Statement I and III,
Let marks in English be x
Marks in Science = x + 12
and marks in Mathematics = x + 32
From Statement II,
E + S + M = 197
x + x + 12 + x + 32 = 197
? 3x + 44 = 197
? 3x = 197 - 44 = 153
? x = 51
? Marks in English = 51
(X + Y)'s 1 day's work = 1/8 ..(i)
(Y + Z)'s 1 day's work = 1/10 ...(ii)
(Z + X)'s 1 day's work = 1/12 ..(iii)
Adding equations i , ii , iii
2(X + Y + Z)'s 1 day's work = 1/8 + 1/10 + 1/12
(X + Y + Z)'s 1 day's work
= 1/2[1/8 + 1/10 + 1/12] ..(iv)
Subtracting Eq. (iii) from Eq. (iv), we get Y's 1 day's work,
Then, required number of days
= 1/Y's 1 day's work
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