Given :- Number of students in college A in the years 2004, 2006 and 2007 = 160 × 103
Also, number of students in college B in the years 2003, 2004 and 2008 = 175 × 103
Required ratio = Number of students in college A in the years 2004, 2006 and 2007 : number of students in college B in the years 2003, 2004 and 2008
= 160 : 175 = 32 : 35
Number of students studying in school B in 1994 = 950 + (350 ? 150) + (225 ? 115) + (185 ? 110) + (200 ? 90) = 950 + 200 + 110 + 75 + 110 = 1445.
Expenditure on the game of Football = 15% of total amount spent
Expenditure on the game of Hockey = 15% of total amount spent
Therefore, the ratio of the expenditure on the two game = 1 : 1
As per given table , we can see that
From State B, post VI has the highest percentage of candidates short listed .
Required answer will be post VI .
Percentage of total increase = (1730 - 1260)/ 1260 x 100 = 470 x 100/ 1260 = 37.3%
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