Required number of students passed in third division = Total number of passed students in 1984 years ? Total number of students passed in first and second division in 1984 years
Required number of students passed in third division = 165 ? 95 = 70
From given graph , we can see that
Since , In 2008 year is the number of students enrolled in all the given 3 districts together the second highest.
Hence required Answer will be 2008 year .
Students enrolled in 2008 in all three districts ( A + B + C ) = 8000 + 6000 + 7000 = 21000
Students enrolled in district B over all the years ( 2005 to 2010 ) = 5000 + 4000 + 7000 + 6000 + 4000 + 7000 = 33000
? Required Difference = Students in district B over all the years ( 2005 to 2010 ) ? Students in 2008 in all 3 districts
? Required Difference = 33000 ? 21000 = 12000
As per given graph, we calculate the difference in two consecutive years import.
In 2003, change in imports = (35 - 30)/35 x 100 = 100/7 = 139/7% fall
In In 2004, change in imports = (40 - 30)/ 50 x 100 = 1/3 x 100 = 331/3% rise
In 2006, change in imports = (55 - 50)/50 x 100 = 10% rise
In 2007, change in imports = (60 - 55/55) x 100 = 91/11% rise
Hence, in 2007 the percentage rise/fall in imports from the previous year is the lowest.
In 2002-03, Total import = 35 + 30 = Rs. 65 crores
Total export = 40 + 55 = Rs. 95 crores
In 2004-05 . Total import = 40 + 50 = Rs. 90 crores
Total export = 35 + 40 = Rs. 75 crores
In 2005-06, Total import = 40 + 50 = Rs. 90 crores
Total export = 40 + 60 = Rs. 100 crores
In 2007-08, Total import = 60 + 45 = Rs. 105 crores
Total export = 50 + 55 = Rs. 105 crores
Hence, in 2007-08 pair of years the total import is equal to total export.
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