As per graph
Average pass percentage of the boys in classes II and III = 70 + 50/2 = 120/2 = 60%
As per given graph we can find that
Average pass percentage of the boys in classes VI and Vii = 50 + 70/2 = 60%
Therefore. average pass percentage of boys in classes II and III is equal to the average pass percentage of girls in classes VI and VII.
Number of candidates :
Delhi ? 15000 + 17000 + 160 + 11000 + 750 = 43910
Hyderabad ? 3500 + 20000 + 300 + 9000 + 1150 = 33950
Katakana ? 14900 + 17650 + 70 + 1300 + 1200 = 35120
Mumbai ? 17000 + 19500 + 70 + 7000 + 900 = 44470
Hence, Mumbai has the highest number of candidates.
Input water full never 35 78 16 height 28
step I full 78 water never 35 78 16 height 28
step II full 78 water never 35 16 height 28
step III full 78 height water never 35 16 28
step IV full 78 height never water 16 28
step V full 78 height never water 16 28
step VI full 78 height 35 never 28 water 16
Hence, Step VI will be the last step.
The data in both the statement I and II together are necessary to answer the question
Even by using both the statements together we can only determine that number of candidates appeared was more than 200.
From I: The possible day of exam is Wednesday.
From II. The third day of the week is Wednesday.
Hence, either statement I alone or statement II alone is sufficient.
Using Statement I: If ken turns 90° towards his right he will face South. So, Ali is facing north.
Using Statement II: In the end Priya faces north. So, Ali also faces north.
It is clear from the pie-chat that percentage of students in college E and percentage of girls in collage is minimum.
Hence, college E has lowest number of girls.
Using Statement I: We cannot determine if all the fiends are facing the centre.
A is the facing outside of C is facing the centre of circle. So, all friends are not facing the centre.
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