If the total amount spent was $ 46000, how much money was spent on clothing and housing together?

From above graph ,
It is clear that the maximum amount was spent on Food , which is 23 % .

From above given graph ,
Given that :- % amount of money spent on housing = 15%
% amount of money spent on education = 12%
Required ratio = % amount of money spent on housing : % amount of money spent on education
Required ratio = 15 : 12 = 5 : 4.

From above given graph ,
The total amount spent on football = 15 %
The total amount spent on Hockey = 15 %
Required ratio = The total amount spent on football : The total amount spent on Hockey
Required ratio = 15 : 15 = 1 : 1.

As per second graph,
Number of girls in course 'C' = Total number of Girls x 2%
Number of girls in course 'C' = 800 x 2/100 = 16

As per first graph,
The number of students for course A = Total number of students x 20%
As per second graph,
The number of girls for course A = Total number of girls x 30%
Number of boys in course 'A' = The number of students for course A - The number of girls for course A
Number of boys in course 'A' = (1200 x 20/100 ) - ( 800 x 30/100 ) = 240 - 240 = 0
Similarly,
Number of boys in course 'B' = (1200 x 15/100 ) - (800 x 10/100) = 180 - 80 = 100
Number of boys in course 'C' = (1200 x 5/100 ) - (800 x 2/100) = 60 - 16 = 44
Number of boys in course 'D' = (1200 x 35/100 ) - (800 x 30/100) = 420 - 240 = 180
Number of boys in course 'E' = (1200 x 12/100 ) - 800 x 14/100 ) = 144 - 112 = 32
Number of boys in course 'F' = (1200 x 13/100 ) - ( 800 x 14/100 ) = 156 - 112 = 44
Hence, number of boys in course 'C' and 'F' are same which is 44.

For course E,
Number of boys = ( 1200 x 12/100 ) - (800 x 14/100 ) = 144 - 112 = 32
Number of girls = 800 x 14/100 = 112
Required percentage = ( (112 - 32 )/32 ) x 100 = (80/32) x 100 = 250%

As per first graph,
The number of students for course A = Total number of students x 20%
As per second graph,
The number of girls for course A = Total number of girls x 30%
Number of boys in course 'A' = The number of students for course A - The number of girls for course A
Number of boys in course 'A' = (1200 x 20/100 ) - ( 800 x 30/100 ) = 240 - 240 = 0
Number of boys in course 'C' = (1200 x 5/100 ) - (800 x 2/100) = 60 - 16 = 44
Number of boys in course 'E' = (1200 x 12/100 ) - 800 x 14/100 ) = 144 - 112 = 32
Number of boys in course 'F' = (1200 x 13/100 ) - ( 800 x 14/100 ) = 156 - 112 = 44
Hence, in course 'A' number of boys is minimum which is Zero.

As per first graph,
The number of students for course D = Total number of students x 20%
As per second graph,
The number of girls for course D = Total number of girls x 30%
Number of boys in course D = The number of students for course D - The number of girls for course D
Number of boys = ( 1200 x 35/100 ) - ( 800 x 30/100 ) = 420 - 240 = 180
Number of girls = 800 x 30/100 = 240
Since, required ratio = 180 : 240 = 3 : 4