In 2008, number of students in Engineering = Total Student x 18%
In 2008, the number of students in Engineering = 35000x18/100 = 6300
In 2009, number of students in Engineering = Total Student x 19%
In 2009, the number of student in Engineering =40000 x19/100 = 7600
Required percentage = (number of students in Engineering in 2009 - number of students in Engineering 2008) x 100 / number of students in Engineering in 2008
Required percentage = (7600 - 3600)x 100 /6300 = 1300/63 = 20.6 ? 20%
It is 36.8% approximately.
Let x be the average height of the class and n be the number of students in the class.
Consider statements I alone
xn - 56 = (x + 1)(x -1)
? x + n = 57 .............(i)
Hence, the value of x cannot be found. So, I alone is not sufficient.
Consider statement I alone:
xn - 42 = (x + 1)(n - 1)
? x - n = 41 .............(ii)
Hence, the value of x cannot be found. So, II alone is not sufficient.
Both the statements together are suficient as the value of x can be found by solving (i) and (ii)
Production of E type cars in 1996 = (100 ? 80)% of 450000
Production of E type cars in 1996 = 20% of 450000 = 90000
And in 1997 = 10% of 520000 = 52000
? Total production = 90000 + 52000 = 142000.
? Required number of cars = 15% of 142000 = 21300
I. Raju can take 4 to 8 days to complete the work.
II. Raju can take 8 to 10 days to complete the work.
Using both the statements together we can determine that Raju took 8 days to complete the work.
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