According to the graph, equal amount has been spent on Hockey and Football because the same percentage given in graph.
Expenditure on the game of Football = 15% of total amount spent
Expenditure on the game of Hockey = 15% of total amount spent
According to the graph, expenditure on cricket is the maximum. Therefore cricket is the most popular game.
According to question, Total spent 100% = 1,20,00,000
According to graph,
? Expenditure on the game of Basketball = 121/2 %
? The Amount spend on the game of Basketball = 121/2% of 1,20,00,000 = 25 x 1,20,00,000/100 = Rs. 15,00,000
According to question the total amount spent = Rs. 30,00,000 = 100%
? Total Expenditure on the games of Cricket and Hockey = 25% + 15% = 40%
? The total amount spend on the games of Cricket and Hockey = 40% of 30,00,000 = 40 x 30,00,000/100 = 40 x 30,000 = Rs. 12,00,000
Expenditure on the game of Football = 15% of total amount spent
Expenditure on the game of Hockey = 15% of total amount spent
Therefore, the ratio of the expenditure on the two game = 1 : 1
As per graph
Expenditure on rent and clothing = 10% + 20% = 30%
Expenditure on medicine and other expenses = 5% + 15% = 20%
? Ratio = 30% : 20% = 3 : 2
As per first graph,
The number of students in Collage A = Total number of students x 21%
As per second graph,
The number of girls from College A = Total number of girls x 23%
So number of boys in Collage A = The total number of students in Collage A - The total number of girls in Collage A.
Number of boys in college A = 3500 x 21/100 - 1800 x 23/100 = 735 - 414 = 321
Similarly we can get the number of boys from other collages.
Number of boys in college B = 3500 x 9/100 - 1800 x 10/100 = 315 - 180 = 135
Number of boys in college C = 3500 x 33/100 - 1800 x 31/100 = 1155 - 558 = 597
Number of boys in college D = 3500 x 18/100 - 1800 x 11/100 = 630 - 198 = 432
Hence, number of boys in college C has maximum.
It is clear from the pie-chat that percentage of students in college E and percentage of girls in collage is minimum.
Hence, college E has lowest number of girls.
As per second graph,
Total number of girls = 1800
Number of girls in College D = Total Number of Girls x 11%
? Number of girls in College D = 1800 x 11%
? Number of girls in College D = 1800 x 11/100
? Number of girls in College D = 18 x 11 = 198
As per first graph,
The number of students in Collage E = Total number of students x 7%
As per second graph,
The number of girls from College E = Total number of girls x 8%
So number of boys in Collage E = The total number of students in Collage E - The total number of girls in Collage E.
Number of boys from college E = 3500 x 7/100 - 1800 x 8/100
Number of boys from college E = 35 x 7 - 18 x 8
Number of boys from college E = 245 - 144 = 101
Similarly for collage F also apply the same formula.
Number of boys from college F = 3500 x 12/100 - 1800 x 17/100 = 420 - 306 = 114
Hence, the total number of boys together in collage E and F = 101 + 114 = 215
As per first graph,
The number of students in Collage A = Total number of students x 21%
The number of students in Collage A = 3500 x 21/100
The number of students in Collage A = 35 x 21 = 735
As per second graph,
The total number of girls from College A = Total number of girls x 23%
The total number of girls from College A = 1800 x 23/100
The total number of girls from College A = 18 x 23 = 414
Number of boys from college A = Total number of students in Collage A - The total number of girls from College A
Since, number of boys from college A = 735 - 414 = 321
Required percentage = 100 x Number of Boys from Collage A / Total number of boys in collage A
Required percentage = 100 x 321/735
Required percentage = 2140/49 = 43.67%
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