Simple interest formula I = P x R x T where
P is the Principal amount of money to be invested at an Interest Rate R% per period for T Number of Time Periods.
Interests earned by Gopal from Company A in 2003 = 25000 x 12 x 1/100
Interests earned by Gopal from Company A in 2003 = 250 x 12 = 3000
Total amount in the end of year 2003 = 25000 + 3000 = 28000
Interests earned by Gopal from Company B in 2004 = 28000 x 14 x 1/100
Interests earned by Gopal from Company B in 2004 = 280 x 14
Interests earned by Gopal from Company B in 2004 = 3920
Total interests accrued by Gopal in 2003 and 2004 from company A and company B = 3000 + 3920
Total interests accrued by Gopal in 2003 and 2004 from company A and company B = Rs. 6920
As per first graph,
The number of students for course D = Total number of students x 20%
As per second graph,
The number of girls for course D = Total number of girls x 30%
Number of boys in course D = The number of students for course D - The number of girls for course D
Number of boys = ( 1200 x 35/100 ) - ( 800 x 30/100 ) = 420 - 240 = 180
Number of girls = 800 x 30/100 = 240
Since, required ratio = 180 : 240 = 3 : 4
Required central angle = Total angle x % of raw material
Required central angle = 360° x 16/100 = 57.6°
Statement I You must see = la pa ni ......... (i)
Did u see = jo ni pa .....................(ii)
From (i) and (ii) you see = pa ni .................(iii)
Using (iii) in (i) , we get must = la
Hence i alone is sufficient.
But II is not even remotely connected with 'must'
Total number of girls enrolled in Painting = 250 + 225 + 150 + 175 + 300 = 1100
Total number of girls enrolled in Stitching = 325 + 250 + 50 + 250+ 325 = 1200
Total number of girls enrolled in Dancing = 150 + 200 + 75 + 400 + 350 = 1175
Hence, required ratio = 1100 : 1200 : 1175 = 44 : 48 : 47
Students enrolled in 2008 in all three districts ( A + B + C ) = 8000 + 6000 + 7000 = 21000
Students enrolled in district B over all the years ( 2005 to 2010 ) = 5000 + 4000 + 7000 + 6000 + 4000 + 7000 = 33000
? Required Difference = Students in district B over all the years ( 2005 to 2010 ) ? Students in 2008 in all 3 districts
? Required Difference = 33000 ? 21000 = 12000
As per second graph,
Number of girls in course 'C' = Total number of Girls x 2%
Number of girls in course 'C' = 800 x 2/100 = 16
Production of C type cars in 1996 = (70 ? 40)% of 450000
Production of C type cars in 1996 = 30% of 450000 = 135000
Production of C type cars in 1997 = (65 ? 40)% of 520000
Production of C type cars in 1997 = 25% of 520000 = 130000
? Required difference = 5000.
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