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- Question
- What is the approximate average profit made by company A in all the years together?
Options- A. Rs. 3,82,000
- B. Rs. 3,98,000
- C. Rs. 4,83,000
- D. Rs. 5,12,000
- Correct Answer
- Rs. 4,83,000
ExplanationAverage profit made by company A in all the years = Rs. (3 + 5 + 4 + 5 + 6 + 6)lakhs/6
= Rs. 29 /6 ? Rs. 4.83 lakh = Rs. 4,83,000 - 1. If the expenditure of company B in the year 2008 was Rs. 22,11, 430, what was its income in that year?
Options- A. Rs. 26,11,430
- B. Rs. 27,11,430
- C. Rs. 28,14,680
- D. Rs. 32,09,670 Discuss
- 2. If the income of company A in the year 2007 was Rs. 13,54,500. what its expenditure in that year?
Options- A. Rs. 6,48,200
- B. Rs. 7,54,300
- C. Rs. 8,33,500
- D. Rs. 921,600 Discuss
- 3. Profit made by Company A in the year 2004 was what percent of the total profit made by all the three companies in that year?
Options- A. 21.43%
- B. 28.24%
- C. 31.25%
- D. 36.25% Discuss
- 4. What is the percent increase in profit of company C in the year 2004 from the previous year?
Options- A. 7
- B. 14
- C. 21
- D. 28 Discuss
- 5. In which of the following years was the difference between the imports made by Company B and C the maximum?
Options- A. 1995
- B. 1994
- C. 1991
- D. 1992 Discuss
- 6. Gopal invested an amount of Rs. 25,000 in company A in 2003 for one year. Thereafter in 2004 he invested the amount along with interest in Company 'B' for one year? What was the total amount of interest earned in the two years together?
Options- A. Rs. 6218.75
- B. Rs. 6800
- C. Rs. 6920
- D. Rs. 7200 Discuss
- 7. In 2007 Saurabh invested an amount of Rs. 12000 in company 'A' and amount of Rs. 15,000 in Company 'B' for one year. What was the total interest accrued?
Options- A. Rs. 3600
- B. Rs. 3800
- C. Rs. 3900
- D. Rs. 4100 Discuss
- 8. Samir invested Rs.10,000 in the company 'A' for one year in 2006. He reinvested the total amount along with interest for next one year in 2007. If he had invested for both years in the Company 'B', what would have been the difference between the interests earned?
Options- A. Rs. 16.50 less
- B. Rs. 116.50 more
- C. Rs. 128.50 less
- D. Rs. 128.50 more Discuss
- 9. An amount of Rs. 20,000 was invested in Company 'B' in 2008 and after one year the entire amount along with interest was will be reinvested in the Company A for one more year. What will be total amount of interest accrued?
Options- A. Rs. 5199
- B. Rs. 5762.50
- C. Rs. 5533.75
- D. Rs. 54.25 Discuss
- 10. Madhava invested Rs. 1500 in Company 'B' in 2005 for two years with a condition to get the compound interest at the same rate as 2005. What was the amount of interest earned?
Options- A. Rs. 4387.75
- B. Rs. 4578.50
- C. Rs. 4578.75
- D. Rs. 4837.50 Discuss
Line chart problems
Search Results
Correct Answer: Rs. 26,11,430
Explanation:
Expenditure of Company B in 2008 = Rs. 22,11,430 and their profit = Rs. 4,00,000
Since, Income = 22,11,430 + 4,00,000 = Rs. 26,11,630
Correct Answer: Rs. 7,54,300
Explanation:
In 2007, income of Company A = Rs. 13,54,300 and their profit = Rs. 6,00,000
Since, their Expenditure = 13,54,300 - 6,00,000 = Rs. 7,54,300
Correct Answer: 31.25%
Explanation:
% Profit made by Company A in the year 2004 = (profit made by A in 2004) x 100/Total profit made by other all 3 companies.
% Profit made by Company A in the year 2004 = 5 x 100/(3 + 5 + 8 ) = 5 x 100/16 = 31.25%
Correct Answer: 14
Explanation:
Rwquired percentage = 8 - 7/7 x 100 = 14.28% ? 14%
Correct Answer: 1992
Explanation:
By visual inspection it is clear that 1992 is the desired year (as the distance between two points is the maximum in 1992).
Hence , Required answer will be 1992.
Correct Answer: Rs. 6920
Explanation:
Simple interest formula I = P x R x T where
P is the Principal amount of money to be invested at an Interest Rate R% per period for T Number of Time Periods.
Interests earned by Gopal from Company A in 2003 = 25000 x 12 x 1/100
Interests earned by Gopal from Company A in 2003 = 250 x 12 = 3000
Total amount in the end of year 2003 = 25000 + 3000 = 28000
Interests earned by Gopal from Company B in 2004 = 28000 x 14 x 1/100
Interests earned by Gopal from Company B in 2004 = 280 x 14
Interests earned by Gopal from Company B in 2004 = 3920
Total interests accrued by Gopal in 2003 and 2004 from company A and company B = 3000 + 3920
Total interests accrued by Gopal in 2003 and 2004 from company A and company B = Rs. 6920
Correct Answer: Rs. 3900
Explanation:
Simple interest formula I = P x R x T where
P is the Principal amount of money to be invested at an Interest Rate R% per period for T Number of Time Periods.
Interests accrued by Saurabh in 2007 from company A = 12000 x 15 x 1/100
Interests accrued by Saurabh in 2007 from company B = 15000 x 14 x 1/100
Total interests accrued by Saurabh in 2007 from company A and company B = ( 12000 x 15 x 1/100 ) + (15000 x 14 x 1/100 )
Total interests accrued by Saurabh in 2007 from company A and company B = ( 120 x 15 ) + (150 x 14 )
Total interests accrued by Saurabh in 2007 from company A and company B = 1800 + 2100
Total interests accrued by Saurabh in 2007 from company A and company B = Rs. 3900
Correct Answer: Rs. 116.50 more
Explanation:
We can apply the formula to calculate the interest amount
I = P x R x t where
A = Total Accrued Amount (principal + interest)
P = Principal Amount
I = Interest Amount
R = Rate of Interest per year as a percent;
t = Time Period involved in years
For Company A in 2006,
Principle amount = 10000
Rate of interest = 11.5 % ( As per given graph for company A in 2006)
Time = 1 year
The interest amount received by Samir in 2007 I = P x R x t
The interest amount received by Samir in 2007 = 10000 x 11.5 x 1/100= 10000 x 115 x 1/10 x 100 = 10 x 115 = 1150
Total amount received by Samir in 2007 = Interest amount + Principal amount = 10000 + 1150 = 11150
Again For Company A in 2007,
Principle amount = 11150
Rate of interest = 15 % ( As per given graph for company A in 2007)
Time = 1 year
The interest amount received by Samir in 2008 I = P x R x t
The interest amount received by Samir in 2008 = 11150 x 15 x 1/100 = 1115 x 15/10 = 1115 x 3/2 = 3345/2 = 1672.5
Total amount received by Samir in 2008 = Interest amount + Principal amount = 11150+ 1672.5 = 12822.50
Hence, their interest = 12822.50 - 10000 = 2822.50
For Company B in 2006,
Principle amount = 10000
Rate of interest = 13.5 % ( As per given graph for company B in 2006)
Time = 1 year
The interest amount received by Samir in 2007 I = P x R x t
The interest amount received by Samir in 2007 = 10000 x 13.5 x 1/100= 10000 x 135 x 1/10 x 100 = 10 x 135 = 1350
Total amount received by Samir in 2007 = Interest amount + Principal amount = 10000 + 1350 = 11350
Again For Company B in 2007,
Principle amount = 11350
Rate of interest = 14 % ( As per given graph for company B in 2007)
Time = 1 year
The interest amount received by Samir in 2008 I = P x R x t
The interest amount received by Samir in 2008 = 11350 x 14 x 1/100 = 1135 x 14/10 = 1135 x 7/5 = 227 x 7 = 1589
Total amount received by Samir in 2008 = Interest amount + Principal amount = 11350+ 1589 = 12939
Since, their interest = 12939 - 10000 = Rs. 2939
Hence, difference between the interests earned = 2939 - 2822.50 = Rs. 116.50
If Samir had invested the amount in company B for both years then he would get Rs. 116.50 more.
Correct Answer: Rs. 5762.50
Explanation:
Simple interest formula I = P x R x T where
P is the Principal amount of money to be invested at an Interest Rate R% per period for T Number of Time Periods.
Interest received in 2009 from Company B = 20000 x 145 x 1/100 = 2900
Hence, their amount = 20000 + 2900 = Rs. 22900
Interest will be received in 2010 from company A = 22900 x 12.5 x 1/100 = Rs. 2862.50
Hence, total amount of interests for both years = 2900 + 2860.50 = Rs. 5762.50
Correct Answer: Rs. 4837.50
Explanation:
Compound interest = P(1 + r)t - P
or Compound interest = P[(1 + r)t - 1]
where P = the principal investment amount (the initial deposit or loan amount)
r = the annual interest rate
t = the number of years the money is invested or borrowed for.
Required amount of interest earned by Madhava in 2007 = 15000[(1+ 15/100)2 - 1]
= 15000[(115/100)2 - 1]
= 15000[(23/20)2 - 1]
= 15000[(23 x 23 /20 x 20) - 1]
= 15000[ (529/400) - 1]
= 15000[(529 - 400)/400]
= 15000 x 129/400
= 19350/4
= Rs. 4837.50
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