As per given Table graph,
Rice produced by state C in years 2006 = 1300
Rice produced by state A in years 2006 = 1700
Required percentage = 1300 x 100 /1700 = 76.47% ? 76%
Total number of female employee = 13363
Required average number of females = 13363/6 = 2227.16
Approx 2227
From above graph ,
Since , In July and August months did all the commodities show decline or no increase from the previous months.
Required answer will be July and August only .
Number of employees working in different organisation are
A ? 1050 + 1017 + 1382 + 1542 + 786 + 48 = 5825
B ? 1015 + 960 + 1384 + 1545 + 745 + 54 = 5703
C ? 976 + 786 + 1275 + 1550 + 801 + 36 = 5424
D ? 888 + 1025 + 1300 + 1570 +800 + 30 = 5613
E ? 1004 + 963 + 1290 + 1580 + 735 + 53 = 5625
Hence, total number of employees = 5825 + 5703 + 5424 + 5613 + 5625 = 28190
In 2008, number of students in Engineering = Total Student x 18%
In 2008, the number of students in Engineering = 35000x18/100 = 6300
In 2009, number of students in Engineering = Total Student x 19%
In 2009, the number of student in Engineering =40000 x19/100 = 7600
Required percentage = (number of students in Engineering in 2009 - number of students in Engineering 2008) x 100 / number of students in Engineering in 2008
Required percentage = (7600 - 3600)x 100 /6300 = 1300/63 = 20.6 ? 20%
It is 36.8% approximately.
Let x be the average height of the class and n be the number of students in the class.
Consider statements I alone
xn - 56 = (x + 1)(x -1)
? x + n = 57 .............(i)
Hence, the value of x cannot be found. So, I alone is not sufficient.
Consider statement I alone:
xn - 42 = (x + 1)(n - 1)
? x - n = 41 .............(ii)
Hence, the value of x cannot be found. So, II alone is not sufficient.
Both the statements together are suficient as the value of x can be found by solving (i) and (ii)
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