As per given table, we can see that,
? Total number of players in School = sum of number of players in given all games
Total number of players in
School A = 150 + 250 + 200 + 100 + 120 = 820
School B = 200 + 125 + 195 + 130 + 180 = 830
School C = 250 + 175 + 245 + 60 + 150 = 880
School D = 230 + 100 + 200 + 40 + 130 = 700
School E = 200 + 250 + 225 + 65 + 165 = 905
Required answer will be School E .
As per given table, we can see that,
Number of students playing Basketball from all the given school
A = 200 , B = 195 , C = 245 , D = 200 , E = 225
Number of students playing Cricket from all the given school
A = 150 , B = 200 , C = 250 , D = 230 , E = 200
The total number of students playing Basketball from all the school = 200 + 195 + 245 + 200 + 225 = 1065
The total number of students playing Cricket from all the school = 150 + 200 + 250 + 230 + 200 = 1030
Required difference = The total number of students playing Basketball from all the school - The total number of students playing Cricket from all the school
Required difference = 1065 ? 1030 = 35
From above given table,
It is clear that state E has the lowest percentage of candidates short listed with respect to candidate eligible for Post IV .
Hence required answer is state E .
As per given table , we can see that
Cricket game is the most popular because number of students playing cricket is more than playing other game .
So , required answer will be cricket .
From above given table ,
Basketball and Badminton are the two games which satisfy the conditions.
Hence , Basketball and Badminton have ascending number of students from class IX to XII.
Given :- The students playing Football in Class XI = 27
The students playing Football in Class X = 18
Required ratio = The students playing Football in Class XI : The students playing Football in Class X
= 27 : 18 = 3 : 2.
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