Discussion
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- Question
- The number of students playing Badminton from School E is p % of the students playing Badminton from School B. Then p equals :
Options- A. 40
- B. 50
- C. 42
- D. 41
- Correct Answer
- 50
Explanation
- 1. The number of students playing Football from School C is a % of the total number of students playing Football from all the schools. Then a equals
Options- A. 19 7 % 9
- B. 19 4 % 9
- C. 18 %
- D. 20 2 % 9 Discuss
- 2. What is the total number of students from all schools who play cricket?
Options- A. 830
- B. 1030
- C. 930
- D. 1130 Discuss
- 3. What was the number of students studying in school B in 1994?
Options- A. 2030
- B. 1060
- C. 1445
- D. 1150 Discuss
- 4. What is the difference in the number of students taking admission between the years 1991 and 1995 in school D and B?
Options- A. 514
- B. 1065
- C. 965
- D. 415 Discuss
- 5. What is the average number of students studying in all the five schools in 1992?
Options- A. 1494
- B. 1294
- C. 1590
- D. 1640 Discuss
- 6. The difference between the total number of students playing Basketball from all the school and the total number of students playing Cricket from all the schools is :
Options- A. 27
- B. 35
- C. 28
- D. 26 Discuss
- 7. Which school has the maximum number of players?
Options- A. A
- B. B
- C. C
- D. E Discuss
- 8. What is the ratio of the total number of candidates short listed for post V to that for post VI from all states together?
Options- A. 6 : 7
- B. 55 : 96
- C. 165 : 278
- D. 16 : 25 Discuss
- 9. The total number of candidates found eligible for Post I from all states together is approximately what percent of total number of candidates found eligible for Post VI from all States together?
Options- A. 45 %
- B. 50 %
- C. 60 %
- D. 55 % Discuss
- 10. What is the overall percentage (rounded off to one digit after decimal) of candidates short listed over the total number of candidates eligible for Post I form all the States together?
Options- A. 9.5 %
- B. 12.5 %
- C. 7.2 %
- D. 6.52 % Discuss
Table Charts problems
Search Results
Correct Answer: 19 4 % 9
Explanation:
Correct Answer: 1030
Explanation:
Total number of students for Cricket = Number of students play cricket from schools ( A + B + C + D + E )
Total number of students for Cricket = 150 + 200 + 250 + 230 + 200
Total number of students for Cricket = 1030
Correct Answer: 1445
Explanation:
Number of students studying in school B in 1994 = 950 + (350 ? 150) + (225 ? 115) + (185 ? 110) + (200 ? 90) = 950 + 200 + 110 + 75 + 110 = 1445.
Correct Answer: 415
Explanation:
Required difference = (340 + 300 + 295 + 320 + 360) ? (350 + 225 + 185 + 200 + 240) = 1615 ? 1200 = 415.
Correct Answer:
Explanation:
Correct Answer: 35
Explanation:
As per given table, we can see that,
Number of students playing Basketball from all the given school
A = 200 , B = 195 , C = 245 , D = 200 , E = 225
Number of students playing Cricket from all the given school
A = 150 , B = 200 , C = 250 , D = 230 , E = 200
The total number of students playing Basketball from all the school = 200 + 195 + 245 + 200 + 225 = 1065
The total number of students playing Cricket from all the school = 150 + 200 + 250 + 230 + 200 = 1030
Required difference = The total number of students playing Basketball from all the school - The total number of students playing Cricket from all the school
Required difference = 1065 ? 1030 = 35
Correct Answer: E
Explanation:
As per given table, we can see that,
? Total number of players in School = sum of number of players in given all games
Total number of players in
School A = 150 + 250 + 200 + 100 + 120 = 820
School B = 200 + 125 + 195 + 130 + 180 = 830
School C = 250 + 175 + 245 + 60 + 150 = 880
School D = 230 + 100 + 200 + 40 + 130 = 700
School E = 200 + 250 + 225 + 65 + 165 = 905
Required answer will be School E .
Correct Answer: 165 : 278
Explanation:
Correct Answer:
Explanation:
Correct Answer: 6.52 %
Explanation:
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