The number of Executives recruited by organisation T in the year 2008 forms approximately what percent of the total number of Executives recruited by all the organisations together in that year?

From above table , we have
Total number of Executives recruited by organisation U in the years 2007 and 2009 = 534 + 510 = 1044
Total number of Executives recruited by organisation P in the years 2007 and 2009 = 506 + 492 = 998
Required ratio = total number of Executives recruited by organisation U in the years 2007 and 2009 : the total number of Executives recruited by organisation P in the same years
Required ratio = 1044 : 998 = 522 : 499

As per given graph , It is clear that Difference between the appeared candidates and qualified candidates in the zone S :
Hence required answer will be 2007 year , which is second lowest ( 270 ).

From above table ,
Number of executives recruited by all given organisations
In year 2006 , P = 480 , Q = 495 , R = 464 , S = 508 , T = 488 , U = 518
In year 2006 , Total number of executives recruited by all the organisations = Sum of the number of executives recruited by all given organisations
= 480 + 495 + 464 + 508 + 488 + 518 = 2953
Hence total executives recruited were 2953.

From above table ,
Number of blue-coloured cars of Model E sold in Metro H = 37
Number of blue-coloured cars of Model D sold in Metro H = 43
Total number of blue-coloured cars of Model E and D sold in Metro H
i.e. Blue (E + D) = 37 + 43 = 80 = White (B).
Hence , The total number of blue-coloured cars of Model E and D sold in Metro H is exactly equal to the number of white-coloured cars of type B model in Metro M .

From above given table , we can see that
Since the minimum difference between the white-coloured cars sold is ( 81 - 80 ) = 1 in B type model.
Hence the correct option is E .