Total number of employees in 2003 = Employees of (Production deptt.+ Sales deptt.+ Procurement deptt.+ Administration & Accounts deptt. + Research & Development deptt.)
Total number of employees in 2003 =150 + 25 + 50 + 45 + 75 = 345
Total number of employees in 2005 = (Production deptt.+ Sales deptt.+ Procurement deptt.+ Administration & Accounts deptt.+ Research & Development deptt.)
Total number of employees in 2005 = 450 + 65 + 30 + 90+ 73 = 708
Hence, it was the year 2005 when total number of employees in the factory became nearly double the total number of employees working in the factory during 2003.
Difference in Required number = Number of Pep-up drink sold in 1990 - Number of Cool-sip drink sold in 1990.
Difference in Required number = 30 million ? 20 million = 10 million.
Difference in Required number = 10 million = 10 x 1000000 ( Since 1 million = 1000000 )
Difference in Required number = 10 million = 10000000
By comparing the Sale of Pep-up for all years and we found that the Sale of Pep-up was the maximum in the year 1989.
Top two highest run scorer are A and E as per given graph.
Total match = 20
Total match played by A if matches having 0's were ignored = 19
Total match played by E if matches having 0's were ignored = 20
Runs Scored by A = 994
Runs Scored by E = 772
Average runs of A = 994 / 19 = 52.3
Average runs of E = 772 / 20 = 38.6
Difference = 52.3 ? 38.6 = 13.7
From above table ,
Number of blue-colour cars of model 'C' sold in Metro M = 50000
Number of red colour cars of model 'F' sold in Metro H = 34000
Required difference = Number of blue-colour cars of model 'C' sold in Metro M ? Number of red colour cars of model 'F' sold in Metro H
= ( 50000 ? 34000 )= 16000.
From the values given in above table , it is clear that during the period 1989?94 , the production of S's car is continuous increase . Hence answer will be S type of cars .
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