Given : -
According to question ,
Total number of students in school = 400 students
Ratio of boys and girls in school = 3 : 5
Let us assume the ration is P.
Number of boys = 3P
Number of girls = 5P
3P + 5P = 400
8P = 400
P = 50
Number of boys = 3P = 3 x 50 =150
Number of girls = 5P = 5 x 50 = 250
% of the boys speak only Hindi = 12%
According to question ,
The total number of boys speaking Hindi
= 12% × Number of boys + six times the number of boys speaking only Hindi
?18 + 108 = 126
Difference in Required number = Number of Pep-up drink sold in 1990 - Number of Cool-sip drink sold in 1990.
Difference in Required number = 30 million ? 20 million = 10 million.
Difference in Required number = 10 million = 10 x 1000000 ( Since 1 million = 1000000 )
Difference in Required number = 10 million = 10000000
By comparing the Sale of Pep-up for all years and we found that the Sale of Pep-up was the maximum in the year 1989.
Top two highest run scorer are A and E as per given graph.
Total match = 20
Total match played by A if matches having 0's were ignored = 19
Total match played by E if matches having 0's were ignored = 20
Runs Scored by A = 994
Runs Scored by E = 772
Average runs of A = 994 / 19 = 52.3
Average runs of E = 772 / 20 = 38.6
Difference = 52.3 ? 38.6 = 13.7
From above table ,
Number of blue-colour cars of model 'C' sold in Metro M = 50000
Number of red colour cars of model 'F' sold in Metro H = 34000
Required difference = Number of blue-colour cars of model 'C' sold in Metro M ? Number of red colour cars of model 'F' sold in Metro H
= ( 50000 ? 34000 )= 16000.
From the values given in above table , it is clear that during the period 1989?94 , the production of S's car is continuous increase . Hence answer will be S type of cars .
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