As per given graph in the question,
Highest run scored by C = 52
Total run scored by C = 414
Number of match played by C if matches having zero runs and the one with highest runs is ignored = 20 - 1 - 2 = 17
Total runs scored by C if matches having zero runs and the one with highest runs is ignored = 414 - 0 - 52 = 362
Average runs of C = 362 / 17 = 21.29
Solve all option one by one.
Ratio of A and D = 141 : 94
Without knowing the individual runs of 8 openers, we cannot find the average runs of remaining batsmen.
Top two highest run scorer are A and E as per given graph.
Total match = 20
Total match played by A if matches having 0's were ignored = 19
Total match played by E if matches having 0's were ignored = 20
Runs Scored by A = 994
Runs Scored by E = 772
Average runs of A = 994 / 19 = 52.3
Average runs of E = 772 / 20 = 38.6
Difference = 52.3 ? 38.6 = 13.7
Given : - According to question ,
Total number of students in school = 400 students
Ratio of boys and girls in school = 3 : 5
Let us assume the ration is P.
Number of boys = 3P
Number of girls = 5P
3P + 5P = 400
8P = 400
P = 50
Number of boys = 3P = 3 x 50 =150
Number of girls = 5P = 5 x 50 = 250
% of the students speak only Hindi = 24%
number of boys speak only Hindi = 18
According to question ,
The total number of girls speaking Hindi
= 24% × Total number of students - number of boys speak only Hindi
= 24% × 400 - 18
= 96 - 18 = 78
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