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- Question
- Approximately what was the average expenditure of the given years?
Options- A. $ 110 Million
- B. $ 130 Million
- C. $ 120 Million
- D. $ 140 Million
- Correct Answer
- $ 130 Million
ExplanationTotal expenditure in 6 years = ( expenditure in 1993 + expenditure in 1994 + expenditure in 1995 + expenditure in 1996 + expenditure in 1997 + expenditure in 1998 ).
As we can see in the given graph that,
Income in 1993 = 120
Profit = 7.5 %
Then Expenditure in 1993 = 120 X 100 / 107.5
Similarly
Expenditure in 1994 = 160 X 100 / 115
Expenditure in 1995 = 130 X 100 / 122.5
Expenditure in 1996 = 170 X 100 / 117.5
Expenditure in 1997 = 190 X 100 / 120
Expenditure in 1998 = 150 X 100 / 127.5
Total Expenditure in 6 years = ( 120 X 100 / 107.5 ) + ( 160 X 100 / 115 ) + ( 130 X 100/122.5 ) + ( 170 X 100 / 117.5 ) + ( 190 X 110 / 120 ) + ( 150 X 100/127.5 )
Total Expenditure in 6 years = 111.6 2 +139.13 + 106.16 + 144.68 + 158.33 + 117.64
Total Expenditure in 6 years = 777.56
Average expenditure per years = 777.56 / 6 = 12 .59 ? $ 130 Million - 1. If the total amount spent during the year was $ 1,20,00,000 how much was spent on basketball?
Options- A. $ 12,50,000
- B. $ 10,00,000
- C. $ 12,00,000
- D. $ 15,00,000 Discuss
- 2. The total number of students who come to school by car is:
Options- A. 70
- B. 290
- C. 420
- D. 480 Discuss
- 3. Which car is 40% more popular than black cars?
Options- A. Blue
- B. Brown
- C. Red
- D. Sliver Discuss
- 4. The percentage of students failed in 1984 was
Options- A. 18 1 % 2
- B. 17 3 % 4
- C. 17 1 % 2
- D. 17% Discuss
- 5. What is the percent increase in the number of products sold by the company in the year 2006 from the previous year? (Rounded off to two digits after decimal)
Options- A. 19.25
- B. 33.33
- C. 10.45
- D. 42.66 Discuss
- 6. The ratio of the total amount of money spent on housing to that spent on education was :
Options- A. 5 : 2
- B. 2 : 5
- C. 4 : 5
- D. 5 : 4 Discuss
- 7. If the income of A in 2005 was Rs. 1,42,500 what was its expenditure in that year?
Options- A. Rs. 95000
- B. Rs. 95500
- C. Rs. 99,500
- D. Rs. 1,05,000 Discuss
- 8. For which course is the number of boys the minimum?
Options- A. A
- B. C
- C. E
- D. F Discuss
- 9. For Company Y, in which year is the percent of increase in percent profit over that of previous year the highest?
Options- A. 2002?03
- B. 1999?2000
- C. 2001?02
- D. Cannot be determined Discuss
- 10. What are the total marks obtained by Tanya in all the subject together?
Options- A. 402
- B. 408
- C. 412
- D. 418 Discuss
More questions
Correct Answer: $ 15,00,000
Explanation:
Correct Answer: 420
Explanation:
Correct Answer: Sliver
Explanation:
Let us assume the car which is 40% more popular than black is a and total number of car is P.
According to question,
(P x a/100 ) - (P x 5/100) = P x 5/100 x 40/100
P(a - 5)x1/100 = P x 5/100 x 40/100
(a - 5) = 5 x 40/100
(a - 5) = 200/100 = 2
a - 5 = 2
a = 2 + 5 = 7
40% more popular than Black cars = 7% popular Silver cars.
Correct Answer: 17 1 % 2
Explanation:
Correct Answer: 33.33
Explanation:
Correct Answer: 5 : 4
Explanation:
From above given graph ,
Given that :- % amount of money spent on housing = 15%
% amount of money spent on education = 12%
Required ratio = % amount of money spent on housing : % amount of money spent on education
Required ratio = 15 : 12 = 5 : 4.
Correct Answer: Rs. 95000
Explanation:
Expenditure = Income - Profit
As per given graph in question,
Income in 2005 = 1,42,500 Rs.
Profit in 2005 = 50%
Let expenditure of Company A in 2005 = Rs. E; then
E + E x 50/ 100 =142500
? E + E x 1/2 =142500
? (2E + E)/2 =142500
? 3E =142500 x 2
? E =142500 x 2/ 3
? E = 47500 x 2
? E = Rs. 95000
Correct Answer: A
Explanation:
As per first graph,
The number of students for course A = Total number of students x 20%
As per second graph,
The number of girls for course A = Total number of girls x 30%
Number of boys in course 'A' = The number of students for course A - The number of girls for course A
Number of boys in course 'A' = (1200 x 20/100 ) - ( 800 x 30/100 ) = 240 - 240 = 0
Number of boys in course 'C' = (1200 x 5/100 ) - (800 x 2/100) = 60 - 16 = 44
Number of boys in course 'E' = (1200 x 12/100 ) - 800 x 14/100 ) = 144 - 112 = 32
Number of boys in course 'F' = (1200 x 13/100 ) - ( 800 x 14/100 ) = 156 - 112 = 44
Hence, in course 'A' number of boys is minimum which is Zero.
Correct Answer: 2001?02
Explanation:
Correct Answer: 412
Explanation:
Total marks obtained by Tanya in all the subjects
= 150 x 60% + 84 + 50 x 80% + 150 x 65% + 125 x 50 + 50 x 76%
Total marks obtained by Tanya in all the subjects
= 150 x 60 /100 + 84 + 50 x 80/100 + 150 x 65/100 + 125 x 50/100 + 50 x 76/100
= 90 + 84 + 40 + 97.5 + 62.5 + 38 = 412
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