The total number of candidates passed from Rural in 1993 and Semi-urban in 1990 was exactly equal to the total number of candidates passed from State capital in which of the following years?

We do not need to calculate the values for each year.
Follow as:
For Rural area : 35% of 5032 ? 35 × 50 = 1750 ? 1798
For Semi-urban area : 35% of 9500 ? 35 × 95 ? 3300
Which cannot be approximated to 3500.
For State capitals : 35 × 85 = 3000
For Metropolises : 35 × 110 = 3850

Our intelligent observation says that the required year cannot be 1993, 1994, 1995. Why? Because see the following conclusions:
% passed to appear = Passed / Appeared x 100
% of passed to appear is least when Passed / Appeared is the least or, Appeared / Passed is the most.
Now, we do the further calculations mentally. See the following conclusions:
For 1990: 7894 / 2513 ? Quotient = 3 and Remainder ? 300
For 1991: 8562 / 2933 ? Q = 3 and R ? 400
For 1992: 8139 / 2468 ? Q = 3 and R ? 800
Similarly, for 1993; 1994, 1995, Q is 2.
So, 1992 gives the highest value.

As we can see in the graph that metropolises location has continuous increase both in appeared and passed.

Obvious from the chart , we can say that 1998?1999 year has the same import and export.

Required difference = Number of B type tyres in 1994 - Number of B type tyres in 1995
Required difference = ( 27.5 ? 22.5 ) Million = 5 Million = 5000000.

Only by visual observation you can find the answer. You do not need to calculate the values. I (iv) (e) Production of B type cars is more than the production of C type cars only in 1993, 1994 and 1995. We see the largest difference exists in 1995. So, the answer is 1995.

As we can see in the graph the maximum chart for the C is in 1995.