Discussion
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- Question
- For the candidates from which of the following locations was there continuous increase both in appeared and passed?
Options- A. Semi-urban
- B. State capital
- C. State capital and Rural
- D. Metropolises
- Correct Answer
- Metropolises
ExplanationAs we can see in the graph that metropolises location has continuous increase both in appeared and passed.
- 1. In which of the following pairs of years the total import is equal to total export in the same pair of years?
Options- A. 1996?1997
- B. 1993?1998
- C. 1998?1999
- D. 1995?1996 Discuss
- 2. During which year the percentage rise/fall in imports from the previous year is the lowest?
Options- A. 1994
- B. 1998
- C. 1997
- D. 1995 Discuss
- 3. Which of the following pairs of years and the % increase in the export over the previous year is correctly matched?
Options- A. 1996 - 14.29
- B. 1997 - 10
- C. 1995 - 33.33
- D. 1994 - 11.11 Discuss
- 4. The total exports in the years 1995, 1996 and 1999 together are what % of the total import during the same period? (up to two decimal places)
Options- A. 107.41
- B. 107.14
- C. 93.33
- D. 93.67 Discuss
- 5. What is the ratio of total imports to total exports for all the given years together?
Options- A. 31 : 35
- B. 35 : 31
- C. 65 : 63
- D. 63 : 65 Discuss
- 6. In which of the following years was the percentage passed to appeared candidates from semi-urban area the least?
Options- A. 1991
- B. 1993
- C. 1990
- D. 1992 Discuss
- 7. What approximate value was the percentage drop in the number of semi-urban candidates appeared from 1991 to 1992?
Options- A. 5
- B. 10
- C. 15
- D. 8 Discuss
- 8. In 1993 percentage of candidates passed to appeared was approximately 35 from which location?
Options- A. Rural
- B. Rural and Metropolises
- C. Semi-urban and Metropolises
- D. Rural and Semi-urban Discuss
- 9. The total number of candidates passed from Rural in 1993 and Semi-urban in 1990 was exactly equal to the total number of candidates passed from State capital in which of the following years?
Options- A. 1990
- B. 1993
- C. 1994
- D. 1992 Discuss
- 10. What was the difference between the number of B type tyres manufactured in 1994 and 1995?
Options- A. 100000
- B. 2000000
- C. 1000000
- D. 1500000 Discuss
Introduction to Data Interpretation problems
Search Results
Correct Answer: 1998?1999
Explanation:
Obvious from the chart , we can say that 1998?1999 year has the same import and export.
Correct Answer: 1998
Explanation:
As per given graph we can see the difference is very less in 1998. Obvious from the chart its 1998 .
Correct Answer: 1996 - 14.29
Explanation:
Correct Answer:
Explanation:
Correct Answer: 63 : 65
Explanation:
Correct Answer: 1990
Explanation:
Our intelligent observation says that the required year cannot be 1993, 1994, 1995. Why? Because see the following conclusions:
% passed to appear = Passed / Appeared x 100
% of passed to appear is least when Passed / Appeared is the least or, Appeared / Passed is the most.
Now, we do the further calculations mentally. See the following conclusions:
For 1990: 7894 / 2513 ? Quotient = 3 and Remainder ? 300
For 1991: 8562 / 2933 ? Q = 3 and R ? 400
For 1992: 8139 / 2468 ? Q = 3 and R ? 800
Similarly, for 1993; 1994, 1995, Q is 2.
So, 1992 gives the highest value.
Correct Answer: 5
Explanation:
Correct Answer:
Explanation:
We do not need to calculate the values for each year.
Follow as:
For Rural area : 35% of 5032 ? 35 × 50 = 1750 ? 1798
For Semi-urban area : 35% of 9500 ? 35 × 95 ? 3300
Which cannot be approximated to 3500.
For State capitals : 35 × 85 = 3000
For Metropolises : 35 × 110 = 3850
Correct Answer: 1994
Explanation:
The total number of candidates passed = Candidates passed from Rural in 1993 + Candidates passed from Semi-urban in 1990
The total number of candidates passed = 1798 + 2513 = 4311.
From the given table graph check the number of passed candidate from state capital is 4311 which is 1994.
Correct Answer:
Explanation:
Required difference = Number of B type tyres in 1994 - Number of B type tyres in 1995
Required difference = ( 27.5 ? 22.5 ) Million = 5 Million = 5000000.
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