Required percentage = (25 + 120) x 100/536 = 100? 27
Here, miscellaneous charges for 4% = 6000
Then advertisement charges for 18% = 6000 x 18/4 = Rs. 27000
Hence, required advertisement charges = Rs. 27000
From above given graph ,
The total amount spent on football = 15 %
The total amount spent on Hockey = 15 %
Required ratio = The total amount spent on football : The total amount spent on Hockey
Required ratio = 15 : 15 = 1 : 1.
? Total boys = 45 + 186 +120 +100 + 65 + 32 + 58 + 5 = 611
? Number of boys who pass in their respective courses = 60% of 611 = 611 x 60/100 = 366.60
Total number of girls = 25 + 23 + 25 + 12 + 25 + 20 + 12 + 3 = 145
Number of girls who pass in their respective courses =70% of 145= 145 x 70/100 = 101.50
? Combined pass percent = (366.6 + 101.5) x 100/(611 + 145) = 46810/756 = 61.92 = 62%
From I : M (+) - P - T ( - )
Combining, we get M ( + ) - P - T ( - )
But II also say's J's husband has one son and two daughters.
Hence, P must be daughter of J.
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